Practice question
Question
In the Carius method, 0.18 g of a compound gave 0.287 g of AgCl. What is the percentage of chlorine?
Explanation
Molar mass of AgCl = 143.5 g/mol, Cl = 35.5 g/mol. Mass of Cl = (35.5/143.5) × 0.287 = 0.071 g. Percentage = (0.071/0.18) × 100 ≈ 39.44% ≈ 40%.
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