In the Carius method, 0.2 g of an organic compound gave 0.235 g of AgCl. What is the percentage of chlorine?
Molar mass of AgCl = 143.5 g/mol, Cl = 35.5 g/mol. Mass of Cl = (35.5/143.5) × 0.235 = 0.058 g. Percentage = (0.058/0.2) × 100 = 29%.
Ref: NCERT Class 11 Chemistry > Chapter 8: Organic Chemistry - Some Basic Principles and Techniques > Topic: Qualitative and Quantitative Analysis - Lassaigne Test and Estimation