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#Carius method

10 public questions tagged with this topic.

In the Carius method, 0.2 g of an organic compound gave 0.235 g of AgCl. What is the percentage of chlorine?

Molar mass of AgCl = 143.5 g/mol, Cl = 35.5 g/mol. Mass of Cl = (35.5/143.5) × 0.235 = 0.058 g. Percentage = (0.058/0.2) × 100 = 29%.

Ref: NCERT Class 11 Chemistry > Chapter 8: Organic Chemistry - Some Basic Principles and Techniques > Topic: Qualitative and Quantitative Analysis - Lassaigne Test and Estimation

In the Carius method, 0.18 g of a compound gave 0.287 g of AgCl. What is the percentage of chlorine?

Molar mass of AgCl = 143.5 g/mol, Cl = 35.5 g/mol. Mass of Cl = (35.5/143.5) × 0.287 = 0.071 g. Percentage = (0.071/0.18) × 100 ≈ 39.44% ≈ 40%.

Ref: NCERT Class 11 Chemistry > Chapter 8: Organic Chemistry - Some Basic Principles and Techniques > Topic: Qualitative and Quantitative Analysis - Lassaigne Test and Estimation

In the estimation of nitrogen by Dumas method, 0.4 g of a compound produces 84 mL of N₂ at STP, and in Carius method, 0.

Mass of N = (28/22400) × 84 = 0.105 g. Percentage = (0.105/0.4) × 100 = 26.25%. (Carius data is a distractor for chlorine.)

Ref: NCERT Class 11 Chemistry > Chapter 8: Organic Chemistry - Some Basic Principles and Techniques > Topic: Qualitative and Quantitative Analysis - Lassaigne Test and Estimation

In the Carius method, 0.6 g of a compound gave 0.717 g of AgI. What is the percentage of iodine?

Molar mass of AgI = 235 g/mol, I = 127 g/mol. Mass of I = (127/235) × 0.717 ≈ 0.387 g. Percentage = (0.387/0.6) × 100 ≈ 64.5%, which rounds to 64%.

Ref: NCERT Class 11 Chemistry > Chapter 8: Organic Chemistry - Some Basic Principles and Techniques > Topic: Qualitative and Quantitative Analysis - Lassaigne Test and Estimation

In the Carius method, 0.15 g of a compound gave 0.287 g of AgCl. If the same sample in Kjeldahl’s method neutralized 10

Mass of Cl = (35.5/143.5) × 0.287 = 0.071 g. Percentage = (0.071/0.15) × 100 = 47.33% ≈ 47%. Kjeldahl’s data is for nitrogen, irrelevant here.

Ref: NCERT Class 11 Chemistry > Chapter 8: Organic Chemistry - Some Basic Principles and Techniques > Topic: Qualitative and Quantitative Analysis - Lassaigne Test and Estimation

In the Carius method, a compound weighing 0.24 g produces 0.47 g of AgCl and 0.233 g of BaSO₄. What is the ratio of chlo

Mass of Cl = (35.5/143.5) × 0.47 ≈ 0.116 g. Mass of S = (32/233) × 0.233 ≈ 0.032 g. Ratio = 0.116/0.032 ≈ 3.625:1, which rounds to 4:1 for practical purposes.

Ref: NCERT Class 11 Chemistry > Chapter 8: Organic Chemistry - Some Basic Principles and Techniques > Topic: Qualitative and Quantitative Analysis - Lassaigne Test and Estimation