Practice question
Question
In the Carius method, 0.3 g of a compound gave 0.574 g of AgBr. What is the percentage of bromine?
Explanation
Molar mass of AgBr = 188 g/mol, Br = 80 g/mol. Mass of Br = (80/188) × 0.574 = 0.244 g. Percentage = (0.244/0.3) × 100 = 81.33%.
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