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#charged conductor

4 public questions tagged with this topic.

Why does the electric field just outside a charged conductor depend only on the surface charge density and not on the to

**Dielectric polarization** when slab inserted, bound charges appear reducing effective field, capacitance increases by factor K, potential difference for constant charge V = Q/C decreases, for constant voltage charge increases. Dielectric constant K = ε/ε₀ >1, e.g., K≈5 for glass. In electrostatic equilibrium, the field just outside a conductor is given by E = (sigma/ε₀) , where sigma is the local surface charge density. This relation arises from Gauss's law applied to a small Gaussian surface at the conductor's surface. The field depends on the charge enclosed per unit area ( sigma ), not the total charge, because the field is determined locally by the

Ref: NCERT > Physics Book > Electrostatic Potential and Capacitance > Conductors, Electrostatic Shielding and Dielectrics

In a system where a charged conductor is placed near an uncharged conductor, why does the uncharged conductor experience

**System of charges** potential energy is sum over pairs U = Σ k q_i q_j/r_ij, work required to assemble charges from infinity. For 28 μC and -14 μC, 0.28 m apart, U=9×10⁹×28×(-14)×10⁻¹²/0.28= -12.6 J, negative indicates bound system. The charged conductor induces charges on the uncharged conductor: opposite charges on the near side and like charges on the far side. The distance between the opposite charges is smaller than between like charges, so the attractive force (proportional to 1/r² ) between opposite charges dominates over the repulsive force between like charges. This imbalance results in a net attractive force, even though the uncharged conductor has

Ref: NCERT > Physics Book > Electrostatic Potential and Capacitance > Potential Energy of System of Charges

What causes the electric field to be stronger near a sharp point on a charged conductor compared to a flat surface?

**Measure of field penetration** depends on both magnitude and projected area. Understanding angle between E and normal vector is crucial, flux zero when field parallel to surface, maximum when perpendicular. Charge concentrates more at sharp points due to lower surface area, increasing the surface charge density. Since the field just outside a conductor is proportional to this density, the field is stronger near points than on flatter regions. Substituting values gives Charge concentration, which matches expected magnitude for this electrostatic configuration, confirming Coulomb's and Gauss's principles and charge quantization consistency.

Ref: NCERT > Physics Book > Electric Charges and Fields > Electric Flux

What causes electric field lines to emerge perpendicularly from the surface of a charged conductor?

**Vector addition of forces** underlies multi-charge analysis. Each pair contributes independent Coulomb force, resultant obtained by resolving components along axes. Equilibrium occurs when vector sum vanishes, often at symmetric points where contributions balance. In equilibrium, the field inside a conductor is zero. Any tangential component outside would drive surface charge motion, violating equilibrium. Thus, the field must be perpendicular to avoid such motion, maintaining static conditions. Substituting values gives Equilibrium condition, which matches expected magnitude for this electrostatic configuration, confirming Coulomb's and Gauss's principles and charge quantization consistency.

Ref: NCERT > Physics Book > Electric Charges and Fields > Superposition Principle and Equilibrium of Charges