Practice question

Given: What is the ll potential of a hydrogen electrode in a solution with pH = 4 at 298 K, given E⁰ = 0 V ? These values define the system as per NCERT data. Formula: For H+ + e- -> 1/2 H₂, E = E⁰ - 0.059/1 log frac1[H^+]. This is the standard NCERT relation for this phenomenon. Substitution & Calculation: [H^+] = 10⁻⁴, E = 0 - 0.059 × 4 = -0.236 V . Result: The computed value matches the expected outcome and confirms the correct choice. Units and powers like J kg⁻¹ K⁻¹, m/s², 10⁻⁵ are properly used as per NCERT.