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Practice question

Question

The boiling point elevation of a 0.15 m aqueous KCl solution is 0.156 K. What is the van't Hoff factor? ( K_b = 0.52 K kg/mol )

Options

Choose one · Correct answer highlighted

Explanation

Given: The boiling point elevation of a 0.15 m aqueous KCl solution is 0.156 K. What is the van't Hoff factor? ( K_b = 0.52 K kg/mol ) These values define the system as per NCERT data. Formula: Δ T_b = i · K_b · m. This is the standard NCERT relation for this phenomenon. Substitution & Calculation: 0.156 = i × 0.52 × 0.15 . i = 0.156/0.52 × 0.15 = 0.156/0.078 = 2 . Result: The computed value matches the expected outcome and confirms the correct choice. Units and powers like J kg⁻¹ K⁻¹, m/s², 10⁻⁵ are properly used as per NCERT.

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