Practice question
Question
The boiling point elevation of a 0.15 m aqueous KCl solution is 0.156 K. What is the van't Hoff factor? ( K_b = 0.52 K kg/mol )
Explanation
Given:
The boiling point elevation of a 0.15 m aqueous KCl solution is 0.156 K. What is the van't Hoff factor? ( K_b = 0.52 K kg/mol )
These values define the system as per NCERT data.
Formula:
Δ T_b = i · K_b · m.
This is the standard NCERT relation for this phenomenon.
Substitution & Calculation:
0.156 = i × 0.52 × 0.15 . i = 0.156/0.52 × 0.15 = 0.156/0.078 = 2 .
Result:
The computed value matches the expected outcome and confirms the correct choice. Units and powers like J kgâ»Â¹ Kâ»Â¹, m/s², 10â»âµ are properly used as per NCERT.
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