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Practice question

MCQ

Question

A thin ring of mass 3kg and radius 0.4m rotates about its center at 5rad/s. What is its rotational kinetic energy?

Options

Choose one · Correct answer highlighted

Explanation

I = MR2 = 3×(0.4)2 = 0.48kg m2. K = 12Iω2 = 12×0.48×(5)2 = 0.24×25 = 6J. As per NCERT, applying relevant law/formula with correct units and sign convention leads to 6.0 J. This satisfies dimensional consistency and physical conditions given, so option B is scientifically correct.

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