Skip to content

Question

A particle in SHM has \( x = 7 \sin (3\pi t + \frac{\pi}{3}) \) (in m). What is its speed at \( t = 0.5
\, \text{s} \)? (Take \( \cos 30^\circ = \frac{\sqrt{3}}{2} \))

Options

Choose one · Correct answer highlighted

Explanation

**SHM representation** using sine or cosine equivalent with phase offset, ω relates to system parameters like mass and stiffness. Understanding ω and φ permits prediction of position at any time and comparison of two SHM via phase difference Δφ = φ₂ - φ₁. Velocity: v = ω A cos (ω t + Φ) . A = 7 m, ω = 3π s⁻¹, Φ = (π/3) . At t = 0.5 : 3π × 0.5 + (π/3) = (3π/2) + (π/3) = (9π/6) + (2π/6) = (11π/6) . v = 3π × 7 cos (11π/6) = 21π cos (180° - 30°) = 21π × (√(3)/2) ≈

Discussion

Comments

0 comments

No comments yet. Be the first to start the discussion.