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Practice question

MCQ

Question

A ball is thrown upwards at 24m/s from a 50m building. How far below the top of the building is it after 6s? (Take g\=10m/s2)

Options

Choose one · Correct answer highlighted

Explanation

Displacement: y=24⋅6−12⋅10⋅(6)2=144−180=−36m. As per NCERT Chapter 3, equations v=u+at, s=ut+½at², v²=u²+2as describe uniformly accelerated motion. Applying correct signs and units gives 36 m as the result, so option A is correct.

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