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Practice question

MCQ

Question

A 10kg mass is suspended by a rope with a 40N horizontal force at its midpoint. What is the angle the rope makes with the vertical? (Take g\=10m/s2)

Options

Choose one · Correct answer highlighted

Explanation

At midpoint: horizontal Tsin⁡θ=40N, vertical Tcos⁡θ=mg=10×10=100N. As per NCERT Chapter 3, equations v=u+at, s=ut+½at², v²=u²+2as describe uniformly accelerated motion. Applying correct signs and units gives 22° as the result, so option B is correct.

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