A 10kg mass is suspended by a rope with a 40N horizontal force at its midpoint. What is the angle the rope makes with th
At midpoint: horizontal Tsinθ=40N, vertical Tcosθ=mg=10×10=100N. As per NCERT Chapter 3, equations v=u+at, s=ut+½at², v²=u²+2as describe uniformly accelerated motion. Applying correct signs and units gives 22° as the result, so option B is correct.
Ref: NCERT Class 11 Physics > Chapter 3: Motion in a Straight Line > Topic: Motion Parameters and Calculations