What is the wavelength of light in water if its wavelength in air is \( 600 \, \text{nm} \) and the refractive index of
**Frequency of light** does not change on refraction, c = f λ, when enters denser medium speed decreases, wavelength decreases λ' = v/f = c/(n f) = λ/n, frequency same, for λ=480 nm f=c/λ=3×10⁸/480×10⁻⁹=6.25×10¹⁴ Hz, for 630 nm f=4.76×10¹⁴ Hz, for 540 nm f=5.56×10¹⁴ Hz, refractive index determines bending. Wavelength in a medium λ_m = (λₐir/n) . Given λₐir = 600 nm , n = 1.33 , λ_m = (600/1.33) ≈ 451 nm . Using Δ = d sinθ, y = n λ D/d, a sinθ = n λ, I = I₀ cos²θ, n = c/v, sinC = 1/n, λ' = λ/n and A =
Ref: NCERT > Physics Book > Wave Optics > Refraction, Refractive Index and Critical Angle
