25 public questions tagged with this topic.
[CoCl₂(en)2]+ has 2 bidentate en (4 donor atoms) and 2 Cl−, totaling 6 ligands. It is octahedral (Co₃+, d6).
Ref: NCERT Class 12 Chemistry > Chapter 5: Coordination Compounds > Topic: Nomenclature of Coordination Compounds
[Co(en)2Cl₂]+ (Co₃+, d6) with 2 en and 2 Cl− is octahedral, and the trans isomer has Cl− ligands opposite each other.
Ref: NCERT Class 12 Chemistry > Chapter 5: Coordination Compounds > Topic: Nomenclature of Coordination Compounds
[Fe(CO)4] (Fe₀, d8) with 4 ligands is tetrahedral, using sp3 hybridization.
Ref: NCERT Class 12 Chemistry > Chapter 5: Coordination Compounds > Topic: Nomenclature of Coordination Compounds
[PtCl₄]2− has Pt in +2 state (d8), with 4 ligands. It adopts a square planar geometry due to dsp2 hybridization, typical for d8 metals like Pt(II).
Ref: NCERT Class 12 Chemistry > Chapter 5: Coordination Compounds > Topic: Bonding - Valence Bond Theory and Hybridisation
[CoF₄]2− (Co₂+, d7) with 4 ligands is tetrahedral, using sp3 hybridization due to weak field F−.
Ref: NCERT Class 12 Chemistry > Chapter 5: Coordination Compounds > Topic: Bonding - Valence Bond Theory and Hybridisation
[Ni(H₂O)4]2+ (Ni₂+, d8) with 4 ligands adopts square planar geometry due to dsp2 hybridization.
Ref: NCERT Class 12 Chemistry > Chapter 5: Coordination Compounds > Topic: Bonding - Valence Bond Theory and Hybridisation
In BeCl₂ , beryllium undergoes sp hybridization, resulting in a linear shape with a 180° bond angle.
Ref: NCERT Class 11 Chemistry > Chapter 4: Chemical Bonding and Molecular Structure > Topic: Valence Bond Theory and Hybridisation - sp sp2 sp3 dsp2
In SO₂ , sulfur is sp² hybridized with one lone pair, reducing the bond angle to about 119° due to lone pair-bond pair repulsion.
Ref: NCERT Class 11 Chemistry > Chapter 4: Chemical Bonding and Molecular Structure > Topic: Valence Bond Theory and Hybridisation - sp sp2 sp3 dsp2
In PCl₃ , phosphorus is sp³ hybridized with 4 electron pairs (3 bonding, 1 lone), resulting in a trigonal pyramidal shape.
Ref: NCERT Class 11 Chemistry > Chapter 4: Chemical Bonding and Molecular Structure > Topic: VSEPR Theory and Shapes of Molecules
In SF₆ , sulfur undergoes sp³d² hybridization, forming an octahedral geometry with 6 fluorine atoms.
Ref: NCERT Class 11 Chemistry > Chapter 4: Chemical Bonding and Molecular Structure > Topic: VSEPR Theory and Shapes of Molecules
In OF₂ , oxygen is sp³ hybridized with 4 electron pairs (2 bonding, 2 lone), resulting in a bent shape.
Ref: NCERT Class 11 Chemistry > Chapter 4: Chemical Bonding and Molecular Structure > Topic: VSEPR Theory and Shapes of Molecules
In IF₅ , iodine is sp³d² hybridized with 6 electron pairs (5 bonding, 1 lone), resulting in a square pyramidal shape.
Ref: NCERT Class 11 Chemistry > Chapter 4: Chemical Bonding and Molecular Structure > Topic: VSEPR Theory and Shapes of Molecules
