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#velocity magnitude

4 public questions tagged with this topic.

A 7kg object moves with a velocity of 3i^−4j^m/s. What is the magnitude of the velocity of its center of mass?

For a single object, the center of mass velocity equals the object’s velocity. Magnitude = (3)2+(−4)2 = 9+16 = 25 = 5m/s. As per NCERT, applying relevant law/formula with correct units and sign convention leads to 5.0 m/s. This satisfies dimensional consistency and physical conditions given, so option B is scientifically correct.

Ref: NCERT Class 11 Physics, Thermal Properties and Gravitation.

A 3kg object moves with a velocity of −5i^−2j^m/s. What is the magnitude of the velocity of its center of mass?

For a single object, the center of mass velocity equals the object’s velocity. Magnitude = (−5)2+(−2)2 = 25+4 = 29≈5.39m/s. As per NCERT, applying relevant law/formula with correct units and sign convention leads to 5.39 m/s. This satisfies dimensional consistency and physical conditions given, so option B is scientifically correct.

Ref: NCERT Class 11 Physics, Thermal Properties and Gravitation.

A particle moves with a constant acceleration of (3i^−2j^)m/s2 from rest. What is the magnitude of its velocity after 4s

Velocity v=v0+at, with v0=0. As per NCERT Chapter 3, equations v=u+at, s=ut+½at², v²=u²+2as describe uniformly accelerated motion. Applying correct signs and units gives 14.42 m/s as the result, so option A is correct.

Ref: NCERT Class 11 Physics > Chapter 3: Motion in a Straight Line > Topic: Motion Parameters and Calculations

A particle starts from rest with a constant acceleration of (−2i^+5j^)m/s2. What is the magnitude of its velocity after

Velocity v=v0+at, with v0=0. As per NCERT Chapter 3, equations v=u+at, s=ut+½at², v²=u²+2as describe uniformly accelerated motion. Applying correct signs and units gives 16.16 m/s as the result, so option A is correct.

Ref: NCERT Class 11 Physics > Chapter 3: Motion in a Straight Line > Topic: Straight Line Motion - Mixed Concepts