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14 public questions tagged with this topic.

A 4kg particle moves with velocity v\=5j^m/s at r\=−3i^m. What is the magnitude of its angular momentum about the origin

L = r×p = |i^j^k^−300050| = k^((−3)×5−0×0) = −15k^kg m2/s. Magnitude = 15kg m2/s. As per NCERT, applying relevant law/formula with correct units and sign convention leads to 15 kg m²/s. This satisfies dimensional consistency and physical conditions given, so option C is scientifically correct.

Ref: NCERT Class 11 Physics, Thermal Properties and Gravitation.

A particle starts from rest with a constant acceleration of (−2i^+5j^)m/s2. What is the magnitude of its velocity after

Velocity v=v0+at, with v0=0. As per NCERT Chapter 3, equations v=u+at, s=ut+½at², v²=u²+2as describe uniformly accelerated motion. Applying correct signs and units gives 16.16 m/s as the result, so option A is correct.

Ref: NCERT Class 11 Physics > Chapter 3: Motion in a Straight Line > Topic: Straight Line Motion - Mixed Concepts