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#temperature conversion

6 public questions tagged with this topic.

Zeroth Law Thermal Equilibrium and Quasi-static

A gas at 4 atm and 27^circ C in a 3 L container is cooled isochorically to -73^circ C . What is the final pressure?

**Thermal equilibrium** achieved when temperatures equal, zeroth law allows definition of temperature, quasi-static process approximates equilibrium at each step, enabling calculation of work as area under P-V curve, reversible processes are quasi-static without dissipative effects. For isochoric: (P₁)/(T₁) = (P₂)/(T₂) . P₁ = 4 atm , T₁ = 27 + 273 = 300 K , T₂ = -73 + 273 = 200 K . (4)/(300) = (P₂)/(200) ⇒ P₂ = (4 × 200)/(300) = (8)/(3) ≈ 2.67 atm . Using first law ΔU = Q - W, W = ∫ P dV, isobaric W = P ΔV, isothermal W = n R T ln(V₂/V₁), adiabatic

Ref: NCERT > Physics Book > Thermodynamics > Zeroth Law Thermal Equilibrium and Quasi-static

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Molecular Mass Density and Ideal Gas Equation

What is the pressure of 0.8 moles of an ideal gas in a 16-litre container at 427°C? (R = 8.31 J mol⁻¹ K⁻¹)

**Molecular mass and density** relation ρ = P M/(R T) allows density calculation, ideal gas law also P = n k_B T where n number density, molecular mass determines mass per molecule, density increases with pressure and decreases with temperature, inverse T dependence. PV = μ R T, P = (μ R T)/(V).T = 427 + 273 = 700 K, V = 16 × 10⁻³ m³.P = (0.8 × 8.31 × 700)/(16 × 10⁻³) = 2.90625 × 10⁵ Pa ≈ 2.91 atm (1 atm ≈ 10⁵ Pa). Substituting values gives 2.91 atm, which matches expected kinetic theory result, confirming mean free path λ = 1/(√2

Ref: NCERT > Physics Book > Behaviour of Perfect Gas and Kinetic Theory > Molecular Mass Density and Ideal Gas Equation

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PHYSICS

What is the Celsius temperature equivalent to 400 K ?

Given: What is the Celsius temperature equivalent to 400 K ? These values define the system as per NCERT data. Formula: Relation: T_C = T - 273.15. This is the standard NCERT relation for this phenomenon. Substitution & Calculation: Given: T = 400 K . T_C = 400 - 273.15 = 126.85° C approx 127° C . Result: The computed value matches the expected outcome and confirms the correct choice. Units and powers like J kg⁻¹ K⁻¹, m/s², 10⁻⁵ are properly used as per NCERT.

Ref: NCERT Physics Textbook for Class XI and XII, Chapter: Units and Measurements and Physical World, Topic: Dimensional analysis and fundamental principles.

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