What is the standard emf of a cell with the reaction Sn(s) + Pb²⁺(aq) → Sn²⁺(aq) + Pb(s) ? (Given: E°Sn²⁺/Sn = -0.14 V ,
E°cell = E°cathode - E°anode = -0.13 - (-0.14) = 0.01 V .
Ref: NCERT Class 12 Chemistry > Chapter 2: Electrochemistry > Topic: Corrosion and Applications of Electrochemistry