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#square arrangement

2 public questions tagged with this topic.

Four charges \( +q, -q, +q, -q \) are at the corners of a square of side \( 2 \, \text{m} \) in order. What is the poten

**Electric potential** V = k Q/r, k = 1/(4π ε₀)=9×10⁹ N·m²/C², Q charge (C), r distance (m), scalar, potential at surface of spherical conductor radius R, V = k Q/R. Potential difference ΔV = V_B - V_A = -∫ E·dl, work per unit charge to move charge without acceleration. Distance from center to each corner = √(2) m . V = 9 × 10⁹ ( (1 × 10⁻⁶/√(2)) + (-1 × 10⁻⁶/√(2)) + (1 × 10⁻⁶/√(2)) + (-1 × 10⁻⁶/√(2)) ) = 0 V . Using V = kQ/r, U = k q₁q₂/r, E = -dV/dr, C = ε₀A/d, 1/C_eq series, C_eq = ΣC parallel,

Ref: NCERT > Physics Book > Electrostatic Potential and Capacitance > Electric Potential and Potential Difference

Four 8kg masses form a square of side 8m. What is the potential energy of the system? (G\=6.67×10−11N m2/kg2)

4 sides: r = 8m, 2 diagonals: r = 82m. V = −4Gm28−2Gm282. V = −6.67×10−11×64(48+282). V = −4.269×10−9(0.5+0.177)≈−2.89×10−9J. As per NCERT, applying relevant law/formula with correct units and sign convention leads to -2.9 × 10⁻⁹ J. This satisfies dimensional consistency and physical conditions given, so option B is scientifically correct.

Ref: NCERT Class 11 Physics, Thermal Properties and Gravitation.