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#shear stress

7 public questions tagged with this topic.

Transverse and Longitudinal Waves

Why can’t transverse waves propagate through a liquid medium?

**Nature of wave** determines energy transfer mechanism. Longitudinal nature of sound explains propagation through fluids with density variations carrying energy, unlike transverse waves needing rigidity for restoring force. Transverse waves require a medium to resist shear deformation (shear modulus). Liquids lack rigidity and cannot sustain shear stress, making transverse wave propagation impossible. Using v = fλ and standing-wave condition fₙ = n v/(2L) or v/(4L) as applicable, calculation yields Due to lack of rigidity, illustrating frequency-length-speed interdependence and quantization b

Ref: NCERT > Physics Book > Waves > Transverse and Longitudinal Waves

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Fluid Pressure, Pascal's Law and Manometers

A plate of area 0.07m2 moves at 0.3m/s over a 0.5mm thick water film (η\=1.0×10−3Pa s). What force is required?

Viscous force: F = ηvAl. η = 1.0×10−3Pa s, v = 0.3m/s, A = 0.07m2, l = 0.5×10−3m. F = 1.0×10−3×0.3×0.070.5×10−3 = 1.0×10−3×42 = 0.042N. As per NCERT, applying relevant law/formula with correct units and sign convention leads to 0.042 N. This satisfies dimensional consistency and physical conditions given, so option B is scientifically correct.

Ref: NCERT Class 11 Physics, Thermal Properties and Gravitation.

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Viscosity, Stokes' Law and Reynolds Number

A plate of area 0.09m2 moves at 0.5m/s over a 0.6mm thick machine oil film (η\=0.113Pa s). What force is required?

Viscous force: F = ηvAl. η = 0.113Pa s, v = 0.5m/s, A = 0.09m2, l = 0.6×10−3m. F = 0.113×0.5×0.090.6×10−3 = 0.113×75 = 8.475N. As per NCERT, applying relevant law/formula with correct units and sign convention leads to 8.5 N. This satisfies dimensional consistency and physical conditions given, so option B is scientifically correct.

Ref: NCERT Class 11 Physics, Thermal Properties and Gravitation.

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Bernoulli's Theorem and Applications

A metal plate of area 0.05m2 moves over a liquid film (η\=0.02Pa s) of thickness 0.2mm at 0.5m/s. What is the force requ

Viscous force: F = ηvAl. η = 0.02Pa s, v = 0.5m/s, A = 0.05m2, l = 0.2×10−3m. F = 0.02×0.5×0.050.2×10−3 = 0.02×125 = 2.5N. As per NCERT, applying relevant law/formula with correct units and sign convention leads to 2.5 N. This satisfies dimensional consistency and physical conditions given, so option B is scientifically correct.

Ref: NCERT Class 11 Physics, Thermal Properties and Gravitation.

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Elastic Properties and Applications

Which modulus is not applicable for describing the elastic behavior of liquids and gases under shear stress?

The shear modulus is not applicable for liquids and gases because they do not sustain shear stress and instead flow; only solids have a defined shear modulus. As per NCERT, applying relevant law/formula with correct units and sign convention leads to Shear modulus. This satisfies dimensional consistency and physical conditions given, so option D is scientifically correct.

Ref: NCBI Bookshelf, Ideal Gas Law: P1V1/T1 = P2V2/T2.

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Shear Modulus and Rigidity

Which type of stress causes a change in the shape of a body without altering its volume?

Shearing stress causes a change in the shape of a body by producing relative displacement of opposite faces (pure shear) without changing its volume. As per NCERT, applying relevant law/formula with correct units and sign convention leads to Shearing stress. This satisfies dimensional consistency and physical conditions given, so option C is scientifically correct.

Ref: NCBI Bookshelf, Ideal Gas Law: P1V1/T1 = P2V2/T2.

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