An aluminium block of dimensions 0.3 m × 0.2 m × 0.05 m is subjected to a shearing force of 1.5 × 10⁴N . If the shear mo
Given: An aluminium block of dimensions 0.3 m × 0.2 m × 0.05 m is subjected to a shearing force of 1.5 × 10⁴N . If the shear modulus of aluminium is 2.5 × 10¹⁰N/m², what is the shear strain? Formula: Shear modulus: G = fracShear stressShear strain. Substitution & Calculation: Shear stress: Shear stress = F/A, A = 0.3 × 0.2 = 0.06 m² . Shear stress: 1.5 × 10⁴/0.06 = 2.5 × 10⁵N/m² . Shear strain: Shear strain = fracShear stressG = frac2.5 × 10⁵².5 × 10¹⁰= 1 × 10⁻⁵. Final Result: The computed value matches expected outcome and confirms correct choice as per latest NCERT 2026-27.
Ref: NCERT Physics Textbook - Latest Edition for Academic Session 2026-27 (Rationalized Textbook for Class XI and XII, continuing as per NCERT advisory for 2026-27),Topic: Fundamental laws, definitions and applications as per latest NCERT. The section explains governing laws, formulas like μ₀ = 4π.
