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#satellite period

2 public questions tagged with this topic.

A satellite near Earth has a period of 89 minutes. What is its period at h\=7RE? (RE\=6.4×106m)

T2∝(RE+h)3. T02 = kRE3, h = 7RE, r = 8RE. T2 = k(8RE)3 = 512kRE3. T = T0512 = 89×22.63≈2014min. As per NCERT, applying relevant law/formula with correct units and sign convention leads to 2010 min. This satisfies dimensional consistency and physical conditions given, so option B is scientifically correct.

Ref: Halliday & Resnick, Fundamentals of Physics, 11th ed., Chapter 13: Gravitation.

A satellite near Earth has a period of 82 minutes. What is its period at h\=9RE? (RE\=6.4×106m)

T2∝(RE+h)3. T02 = kRE3, h = 9RE, r = 10RE. T2 = k(10RE)3 = 1000kRE3. T = T01000 = 82×31.62≈2593min. As per NCERT, applying relevant law/formula with correct units and sign convention leads to 2590 min. This satisfies dimensional consistency and physical conditions given, so option B is scientifically correct.

Ref: Halliday & Resnick, Fundamentals of Physics, 11th ed., Chapter 13: Gravitation.