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#right-hand rule

5 public questions tagged with this topic.

In an electromagnetic wave, if the electric field oscillates along the \( y \)-axis and the wave propagates along the \(

**EM wave in vacuum** transverse, E and B perpendicular to propagation and to each other, E×B along propagation, in phase, E/B = c =3×10⁸ m/s, c =1/√(μ₀ ε₀), μ₀=4π×10⁻⁷ H/m, ε₀=8.85×10⁻¹² F/m. For E₀=45 V/m, B₀=E₀/c=45/3×10⁸=1.5×10⁻⁷ T=150 nT, illustrating B much smaller than E. In an EM wave, E , B , and the direction of propagation are perpendicular. If E is along y -axis and propagation is along x -axis, then B must be along z -axis ( E × B gives propagation direction). Using c = fλ, E₀/B₀ = c, I_d = ε₀ dΦ_E/dt, and spectrum classification λ = c/f, evaluation yields z

Ref: NCERT > Physics Book > Electromagnetic Waves > EM Wave Characteristics - Transverse Nature and E/B Ratio

An electromagnetic wave propagates in the \( z \)-direction with electric field along the \( x \)-axis. In which directi

**EM wave in vacuum** transverse, E and B perpendicular to propagation and to each other, E×B along propagation, in phase, E/B = c =3×10⁸ m/s, c =1/√(μ₀ ε₀), μ₀=4π×10⁻⁷ H/m, ε₀=8.85×10⁻¹² F/m. For E₀=45 V/m, B₀=E₀/c=45/3×10⁸=1.5×10⁻⁷ T=150 nT, illustrating B much smaller than E. In an electromagnetic wave, E , B , and the direction of propagation are mutually perpendicular. If E is along x -axis and propagation is along z -axis, then B must be along the y -axis (since E × B gives the direction of propagation). Using c = fλ, E₀/B₀ = c, I_d = ε₀ dΦ_E/dt, and spectrum classification λ =

Ref: NCERT > Physics Book > Electromagnetic Waves > EM Wave Characteristics - Transverse Nature and E/B Ratio

Which rule is used to determine the direction of the magnetic field produced by a current-carrying straight wire?

**Lorentz force** on charge q moving with velocity v in magnetic field B is F = q v × B, magnitude F = q v B sinθ, θ angle between v and B (degrees), unit N. Direction perpendicular to both v and B via right-hand rule. When v ⊥ B, motion circular with radius r = m v/(q B), centripetal force provided by magnetic force. The direction of the magnetic field around a current-carrying straight wire is determined by the right-hand rule: grasp the wire with your right hand, thumb pointing in the direction of the current, and your fingers curl in the direction of

Ref: NCERT > Physics Book > Moving Charge and Magnetism > Magnetic Force on Moving Charge - Lorentz Force and Motion

Vectors a\=4i^−2j^ and b\=3i^+5j^ are given. What is the direction of a×b?

a×b = |i^j^k^4−20350| = k^(4×5−(−2)×3) = k^(20+6) = 26k^. Direction is along the positive z-axis (k^). As per NCERT, applying relevant law/formula with correct units and sign convention leads to k^. This satisfies dimensional consistency and physical conditions given, so option D is scientifically correct.

Ref: NCERT Class 11 Physics, Thermal Properties and Gravitation.