A 9 Ω resistor dissipates 36 W of power. What is the current through it?
Given: A 9 Ω resistor dissipates 36 W of power. What is the current through it? These values define the system as per NCERT data. Formula: Power: P = I² R. This is the standard NCERT relation for this phenomenon. Substitution & Calculation: Rearrange: I = sqrtP/R . Substitute: I = sqrt36/9 = sqrt4 = 2 A . Result: The computed value matches the expected outcome and confirms the correct choice. Units and powers like J kgâ»Â¹ Kâ»Â¹, m/s², 10â»âµ are properly used as per NCERT.
Ref: NCERT Physics Textbook for Class XI and XII, Chapter: Current Electricity, Topic: Resistivity, temperature dependence and circuit analysis.