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#relaxation time

2 public questions tagged with this topic.

In a conductor, if the number of free electrons per unit volume doubles while the electric field and relaxation time rem

**Current and drift relation** I = n e A v_d shows current proportional to drift velocity and area. For A=6×10⁻⁷ m², I=1.8 A, n=8.5×10²⁸ m⁻³, v_d =1.8/(8.5×10²⁸×1.6×10⁻¹⁹×6×10⁻⁷)=2.2×10⁻⁴ m/s, illustrating small drift speed even for ampere currents. Current density j = n e v_d , where v_d = e E tau / m . If n doubles and E , tau , and m remain constant, v_d is unchanged, so j' = 2n e v_d = 2j . Thus, current density doubles. Applying I = n e A v_d, R = ρ l/A, R_t = R₀[1+αΔT], Kirchhoff's ΣI=0, ΣV=0, R_eq series/parallel, V = ε - I

Ref: NCERT > Physics Book > Current Electricity > Electric Current, Drift Velocity and Mobility

What is the significance of the relaxation time in the context of electron drift in a conductor?

**Mobility** μ = v_d/E = e τ/m, τ relaxation time (s), measures ease of electron drift under field E (V/m). Conductivity σ = n e μ = 1/ρ, linking microscopic τ to macroscopic resistivity, explaining why metals conduct well due to large n and τ. Relaxation time ( tau ) is the average time between electron collisions with lattice ions. It determines drift velocity ( v_d = e E tau / m ), affecting how quickly electrons respond to the field and thus the conductor’s conductivity. Applying I = n e A v_d, R = ρ l/A, R_t = R₀[1+αΔT], Kirchhoff's ΣI=0, ΣV=0, R_eq series/parallel,

Ref: NCERT > Physics Book > Current Electricity > Electric Current, Drift Velocity and Mobility