10 public questions tagged with this topic.
x = 0.8, pA = 1.2. k ≈ 0.00675 s⁻¹.
Ref: NCERT Class 12 Chemistry > Chapter 3: Chemical Kinetics > Topic: Temperature Dependence - Arrhenius Equation and Activation Energy
For A → 2B, x = 0.5, pA = 0.5. k ≈ 0.0139 s⁻¹.
Ref: NCERT Class 12 Chemistry > Chapter 3: Chemical Kinetics > Topic: Rate of Reaction - Average and Instantaneous Rate and Rate Law
For A → B + C, x = 0.5 atm, pA = 1.5 atm. k = (2.303/20) log(2.0/1.5) ≈ 0.0203 s⁻¹.
Ref: NCERT Class 12 Chemistry > Chapter 3: Chemical Kinetics > Topic: Rate of Reaction - Average and Instantaneous Rate and Rate Law
x = 0.2, pA = 0.6. k ≈ 0.0096 s⁻¹.
Ref: NCERT Class 12 Chemistry > Chapter 3: Chemical Kinetics > Topic: Pseudo First Order and Complex Reactions
x = 0.4, pA = 0.8. k ≈ 0.0081 s⁻¹.
Ref: NCERT Class 12 Chemistry > Chapter 3: Chemical Kinetics > Topic: Order and Molecularity and Units of Rate Constant
For A → 2B, x = 0.6, pA = 0.6. k ≈ 0.0231 s⁻¹.
Ref: NCERT Class 12 Chemistry > Chapter 3: Chemical Kinetics > Topic: Order and Molecularity and Units of Rate Constant
x = 0.4, pA = 0.4. k ≈ 6.93 × 10⁻³ s⁻¹.
Ref: NCERT Class 12 Chemistry > Chapter 3: Chemical Kinetics > Topic: Integrated Rate Equations - Zero Order Reactions
x = 0.6, pA = 1.8. k ≈ 0.0072 s⁻¹.
Ref: NCERT Class 12 Chemistry > Chapter 3: Chemical Kinetics > Topic: Integrated Rate Equations - Zero Order Reactions
Initial x = (5/500) = 0.01 . New x = (10/500) = 0.02 . Percentage increase = (0.02 - 0.01/0.01) × 100 = 100% .
Ref: NCERT Class 12 Chemistry > Chapter 1: Solutions > Topic: Solubility - of Solids and Gases in Liquids Henry's Law
Let PB = PC = p , PA = 1 - p , total pressure = (1 - p) + p + p = 1 + p = 1.5 , p = 0.5 . PA = 0.5 atm , PB = PC = 0.5 atm . Kp = (PB PC/PA) = ((0.5)(0.5)/0.5) = 0.5 .
Ref: NCERT Class 11 Chemistry > Chapter 6: Equilibrium > Topic: Physical Equilibrium - Solid-Liquid Gas-Liquid and Henry's Law
