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#polarizers

3 public questions tagged with this topic.

What is the intensity of light after passing through three polaroids, with the first and third crossed and the second at

**Two polaroids** with pass-axes perpendicular intensity zero because second blocks component, with 45° intensity I₀/4 if initial after first I₀, if initial unpolarized I₀, after first I₀/2 then after second at 45° I₀/4. Three polaroids first and third crossed 90°, middle at 45° maximum transmission because middle rotates polarization, I after first I₀/2, after middle at 45° I₀/4, after third at 45° to middle I₀/4×cos²45°= I₀/8, non-zero, maximum when middle 45°. After the first polaroid, I = (I₀/2) . After the second at 45° , I = (I₀/2) cos² 45° = (I₀/4) . Third at 90° - 45° = 45° to second,

Ref: NCERT > Physics Book > Wave Optics > Polarization and Malus Law

What is the intensity of light after passing through two polaroids with pass-axes at \( 75^\circ \), if the initial unpo

**Two polaroids** with pass-axes perpendicular intensity zero because second blocks component, with 45° intensity I₀/4 if initial after first I₀, if initial unpolarized I₀, after first I₀/2 then after second at 45° I₀/4. Three polaroids first and third crossed 90°, middle at 45° maximum transmission because middle rotates polarization, I after first I₀/2, after middle at 45° I₀/4, after third at 45° to middle I₀/4×cos²45°= I₀/8, non-zero, maximum when middle 45°. After the first polaroid, I = (I₀/2) . After the second at 75° , I = (I₀/2) cos² 75° . cos 75° ≈ 0.259 , I = (I₀/2) × (0.259)² = (I₀

Ref: NCERT > Physics Book > Wave Optics > Polarization and Malus Law

What is the intensity of light after passing through two polaroids with pass-axes at \( 60^\circ \), if the intensity af

**Polaroid rotation** intensity varies sinusoidally with angle due to Malus law I = I₀ cos²θ, when polaroid rotated 90° from initial, intensity goes from max to zero, for unpolarized light rotating polaroid does not change intensity after first polaroid because average, but second polaroid intensity depends on relative angle, explains why intensity transmitted through two polaroids drops to zero when perpendicular. Using Malus’ law, I = I₀ cos² θ . For θ = 60° , cos 60° = 0.5 , I = I₀ (0.5)² = 0.25 I₀ . Using Δ = d sinθ, y = n λ D/d, a sinθ = n λ, I =

Ref: NCERT > Physics Book > Wave Optics > Polarization and Malus Law