What is the intensity of light after passing through two polaroids with pass-axes at \( 60^\circ \), if the initial unpo
**Two polaroids** with pass-axes perpendicular intensity zero because second blocks component, with 45° intensity I₀/4 if initial after first I₀, if initial unpolarized I₀, after first I₀/2 then after second at 45° I₀/4. Three polaroids first and third crossed 90°, middle at 45° maximum transmission because middle rotates polarization, I after first I₀/2, after middle at 45° I₀/4, after third at 45° to middle I₀/4×cos²45°= I₀/8, non-zero, maximum when middle 45°. After the first polaroid, I = (I₀/2) . After the second at 60° , I = (I₀/2) cos² 60° = (I₀/2) × (1/4) = (I₀/8) . Using Δ = d sinθ, y
Ref: NCERT > Physics Book > Wave Optics > Polarization and Malus Law