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For NaOH , [OH-] = 0.001 M = 10⁻³ M , so pOH = -log(10⁻³) = 3 .
Ref: NCERT Class 11 Chemistry > Chapter 6: Equilibrium > Topic: Acid-Base Theories - Arrhenius Bronsted-Lowry Lewis and Salts Hydrolysis
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