A 3kg particle has a velocity v\=2i^m/s at position r\=4j^m. What is the magnitude of its angular momentum about the ori
L = r×p = r×(mv) = |i^j^k^040200| = −8k^kg m2/s. Magnitude = 8kg m2/s. As per NCERT, applying relevant law/formula with correct units and sign convention leads to 8 kg m²/s. This satisfies dimensional consistency and physical conditions given, so option B is scientifically correct.
Ref: NCERT Class 11 Physics, Thermal Properties and Gravitation.