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Moles of solute = (12/60) = 0.2 mol . Molality = (0.2/0.2) =appendicitis = 1 mol/kg . Δ Tf = Kf · m = 1.86 × 1 = 1.86 K .
Ref: NCERT Class 12 Chemistry > Chapter 1: Solutions > Topic: Colligative Properties - Depression of Freezing Point
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