A 0.2 M NaCl solution is diluted by adding 150 mL of water to 50 mL of the original solution. What is the final molarity
M₁V₁ = M₂V₂. 0.2 × 50 = M₂ × (50 + 150). M₂ = (0.2 × 50)/200 = 0.05 M.
Ref: NCERT Class 11 Chemistry > Chapter 1: Some Basic Concepts of Chemistry > Topic: Stoichiometry and Stoichiometric Calculations and Limiting Reagent
