A 0.2 molal solution of NaBr in water has a freezing point depression of 0.744°C. What is the van’t Hoff factor? ( Kf =
Δ Tf = i · Kf · m . 0.744 = i × 1.86 × 0.2 . i = (0.744/1.86 × 0.2) = 2 .
Ref: NCERT Class 12 Chemistry > Chapter 1: Solutions > Topic: Colligative Properties - Depression of Freezing Point