#methanol

Chemical Reactions of Alcohols - Dehydration Oxidation Esterification

Which factor explains the lower boiling point of methanol compared to ethanol?

Methanol (CH₃OH) has a lower molecular weight (32 g/mol) than ethanol (CH₃CH₂OH, 46 g/mol), reducing van der Waals forces and thus lowering its boiling point.

Ref: NCERT Class 12 Chemistry > Chapter 7: Alcohols, Phenols and Ethers > Topic: Chemical Reactions of Alcohols - Dehydration Oxidation Esterification

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Nature of C-X Bond and Methods of Preparation

What is the product when CH₃CH₂CH₂I reacts with NaOCH₃ in methanol?

NaOCH₃ substitutes I in CH₃CH₂CH₂I via SN₂ , forming CH₃CH₂CH₂OCH₃ (methyl propyl ether).

Ref: NCERT Class 12 Chemistry > Chapter 6: Haloalkanes and Haloarenes > Topic: Nature of C-X Bond and Methods of Preparation

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Elimination Reactions and Reaction with Metals and Other Reactions

What is the product when CH₃CH₂CH₂Br reacts with KOH in methanol?

Alcoholic KOH (in methanol) promotes elimination (E₂) in CH₃CH₂CH₂Br , forming CH₃CH=CH₂ (propene).

Ref: NCERT Class 12 Chemistry > Chapter 6: Haloalkanes and Haloarenes > Topic: Elimination Reactions and Reaction with Metals and Other Reactions

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Elimination Reactions and Reaction with Metals and Other Reactions

What is the product when CH₃CH₂I reacts with NaOCH₃ in methanol?

NaOCH₃ in methanol substitutes I in CH₃CH₂I via SN₂ , forming CH₃CH₂OCH₃ (ethyl methyl ether).

Ref: NCERT Class 12 Chemistry > Chapter 6: Haloalkanes and Haloarenes > Topic: Elimination Reactions and Reaction with Metals and Other Reactions

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Colligative Properties - Relative Lowering and Elevation of Boiling Point

What is the mole fraction of methanol (molar mass = 32 g/mol) in a solution containing 16 g of methanol and 72 g of wate

Moles of methanol = (16/32) = 0.5 mol . Moles of water = (72/18) = 4 mol . Total moles = 0.5 + 4 = 4.5 . Mole fraction = (0.5/4.5) ≈ 0.111 .

Ref: NCERT Class 12 Chemistry > Chapter 1: Solutions > Topic: Colligative Properties - Relative Lowering and Elevation of Boiling Point

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Abnormal Molar Masses and van't Hoff Factor

A solution contains 32 g of methanol (molar mass = 32 g/mol) and 90 g of water. If the mole fraction of methanol is to b

Initial moles of methanol = (32/32) = 1 . Moles of water = (90/18) = 5 . Let additional moles of methanol = x . New mole fraction = (1 + x/1 + x + 5) = 0.3 . 1 + x = 0.3 (6 + x) , 1 + x = 1.8 + 0.3x , 0.7x = 0.8 , x ≈ 1.1429 . Mass added = 1.1429 × 32 ≈ 36.57 g .

Ref: NCERT Class 12 Chemistry > Chapter 1: Solutions > Topic: Abnormal Molar Masses and van't Hoff Factor

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Abnormal Molar Masses and van't Hoff Factor

A solution contains 23 g of methanol (molar mass = 32 g/mol) and 72 g of water. If 64 g of water is added, what is the n

Moles of methanol = (23/32) ≈ 0.7188 . Initial moles of water = (72/18) = 4 . New moles of water = (72 + 64/18) = (136/18) ≈ 7.5556 . Total moles = 0.7188 + 7.5556 ≈ 8.2744 . Mole fraction = (0.7188/8.2744) ≈ 0.0869 .

Ref: NCERT Class 12 Chemistry > Chapter 1: Solutions > Topic: Abnormal Molar Masses and van't Hoff Factor

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Concentration Terms - Molarity Molality and Mole Fraction

What is the mole fraction of CH₃OH in a solution containing 16 g of CH₃OH and 36 g of H₂O? (Molar masses: CH₃OH = 32 g/m

Moles of CH₃OH = 0.5 mol; moles of H₂O = 2 mol. Total moles = 2.5. Mole fraction = 0.5/2.5 = 0.2.

Ref: NCERT Class 11 Chemistry > Chapter 1: Some Basic Concepts of Chemistry > Topic: Concentration Terms - Molarity Molality and Mole Fraction

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