The conductivity of a 0.005 M KBr solution is 0.00072 S cm⁻¹. What is the molar conductivity?
Lambdam = (kappa × 1000/c) = (0.00072 × 1000/0.005) = 144 S cm² mol⁻¹ .
Ref: NCERT Class 12 Chemistry > Chapter 2: Electrochemistry > Topic: Conductance - Conductivity Molar Conductivity and Kohlrausch Law