4 public questions tagged with this topic.
Pent-1-ene (CH₂=CHCH₂CH₂CH₃) reacts with H₂SO₄ and H₂O via acid-catalyzed hydration, adding -OH to the second carbon (Markovnikov’s rule) to form pentan-2-ol.
Ref: NCERT Class 12 Chemistry > Chapter 7: Alcohols, Phenols and Ethers > Topic: Preparation of Alcohols - from Alkenes Haloalkanes Carbonyls Grignard
Acid-catalyzed hydration follows Markovnikov’s rule, giving propan-2-ol. Hydroboration-oxidation gives propan-1-ol (anti-Markovnikov).
Ref: NCERT Class 12 Chemistry > Chapter 7: Alcohols, Phenols and Ethers > Topic: Preparation of Alcohols - from Alkenes Haloalkanes Carbonyls Grignard
2-Methylpropene (CH₂=C(CH₃)CH₃) undergoes acid-catalyzed hydration with H₂SO₄ and H₂O, following Markovnikov’s rule, to form 2-methylpropan-2-ol ((CH₃)3COH).
Ref: NCERT Class 12 Chemistry > Chapter 7: Alcohols, Phenols and Ethers > Topic: Chemical Reactions of Phenols and Ethers and Uses
1-Butene (CH₂=CH-CH₂-CH₃) undergoes acid-catalyzed hydration with H₂SO₄ and H₂O, following Markovnikov’s rule, to form butan-2-ol (CH₃CH(OH)CH₂CH₃).
Ref: NCERT Class 12 Chemistry > Chapter 7: Alcohols, Phenols and Ethers > Topic: Chemical Reactions of Alcohols - Dehydration Oxidation Esterification
