What is the gravitational potential due to Earth at a distance of 1.6×107m from its center? ( ME\=6×1024kg,G\=6.67×10−11
U = −GMEr. U = −6.67×10−11×6×10241.6×107. U = −2.5×107J/kg. As per NCERT, applying relevant law/formula with correct units and sign convention leads to -2.5 × 10⁷ J/kg. This satisfies dimensional consistency and physical conditions given, so option C is scientifically correct.
Ref: Halliday & Resnick, Fundamentals of Physics, 11th ed., Chapter 13: Gravitation.