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#Gas Reactions

2 public questions tagged with this topic.

CHEMISTRY

A gaseous reaction follows Rate = k p_A p_B with k = 0.04 atm^{-1 s^{-1, p_A = 0.5 atm, and p_B = 0.2 atm . What is the

Given: A gaseous reaction follows Rate = k p_A p_B with k = 0.04 atm^{-1 s^{-1, p_A = 0.5 atm, and p_B = 0.2 atm . What is the rate in atm s^{-1 ? These values define the system as per NCERT data. Formula: Rate = k p_A p_B = 0.04 × 0.5 × 0.2 = 0.004 .. This is standard NCERT relation. Substitution & Calculation: Substituting values and simplifying step by step as per NCERT method. Result: The computed value matches expected outcome and confirms correct choice as per NCERT.

Ref: NCERT Chemistry Textbook for Class XI and XII, Chapter: Some Basic Concepts, Structure of Atom, Periodicity and relevant Chemistry topic, Topic: Mole concept and periodic trends.

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CHEMISTRY

For the reaction Nâ‚‚(g) + 2Oâ‚‚(g) 2NOâ‚‚(g), K_c = 0.04 at 500 K. If initial concentrations are [Nâ‚‚] = 0.2 M and [Oâ

Given: For the reaction N₂(g) + 2O₂(g) 2NO₂(g), K_c = 0.04 at 500 K. If initial concentrations are [N₂] = 0.2 M and [O₂] = 0.3 M, what is [NO₂] at equilibrium? These values define the system as per NCERT data. Formula: Let [NO₂] = 2x, then [N₂] = 0.2 - x, [O₂] = 0.3 - 2x. This is the standard NCERT relation for this phenomenon. Substitution & Calculation: K_c = frac[NO₂]²[N₂][O₂]² = (2x)²/(0.2 - x)(0.3 - 2x)² = 0.04 . Simplify: 4x² = 0.04 (0.2 - x)(0.3 - 2x)², solve: x approx 0.015, 2x approx 0.03 M. Result: The computed value matches the expect

Ref: NCERT Chemistry Textbook for Class XI and XII, Chapter: Thermodynamics, Equilibrium and Chemical Kinetics, Topic: Energetics, equilibrium constants and reaction rates.

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