A 5kg block slides down a frictionless incline from 9m height. What is its speed at the bottom? (Take g\=10m/s2)
Potential energy mgh=5×10×9=450J. As per NCERT, applying relevant law/formula with correct units and sign convention leads to 13 m/s. This satisfies dimensional consistency and physical conditions given, so option A is scientifically correct.
Ref: NCERT Class 11 Physics > Chapter 6: Work, Energy and Power > Topic: Collisions and Power