Skip to content

#foraging behavior

2 public questions tagged with this topic.

If a predator prefers prey1 regardless of prey2 abundance, it is due to:

In the optimal diet model, prey are ranked by expected energetic return per unit handling time, E/h. If E1/h1 exceeds E2/h2, prey 1 is the higher-ranked item and should be accepted whenever encountered. This profitability difference explains a persistent preference, but the phrase “regardless of prey2 abundance” reflects an additional prediction: acceptance of a lower-ranked prey generally depends on encounter rates with the more profitable prey, not on how abundant the lower-ranked prey itself is. When prey 1 is sufficiently common, a predator can reject prey 2 and spend search time seeking p

Ref: Ecology: Concepts and Applications, Molles, 9th Ed., Ch. 14

A predator will prefer prey type P1 over P2 if:

Optimal diet theory ranks prey by profitability, usually E_i/h_i, where E_i is usable energy from prey type i and h_i is handling time. Prey type P1 ranks above P2 when E1/th1 exceeds E2/th2, because each unit of post-encounter time devoted to P1 yields more energy. The ratio, not the sum or product of energy and handling time, captures energetic return rate. A predator encountering the higher-ranked type should accept it under the basic model. Whether it also accepts the lower-ranked type depends mainly on the encounter rate with higher-ranked prey: abundant P1 can make rejecting P2 worthwhil

Ref: Ecology: Concepts and Applications, Molles, 9th Ed., Ch. 14