What mass of Fe can be obtained from 16 g of Fe₂O₃ using excess CO? (Molar masses: Fe₂O₃ = 160 g/mol, Fe = 56 g/mol)
Reaction: Fe₂O₃ + 3CO → 2Fe + 3CO₂. Moles of Fe₂O₃ = 16/160 = 0.1 mol. 0.1 mol Fe₂O₃ produces 0.2 mol Fe = 0.2 × 56 = 11.2 g.
Ref: NCERT Class 11 Chemistry > Chapter 1: Some Basic Concepts of Chemistry > Topic: Stoichiometry and Stoichiometric Calculations and Limiting Reagent
