For a reaction with Δ H = -50 kJ/mol and Δ S = -100 J/K, at what temperature does Δ G = 0?
Δ G = Δ H - TΔ S = 0, -50 × 10³ - T(-100) = 0, T = 50000 / 100 = 500 K.
Ref: NCERT Class 11 Chemistry > Chapter 5: Thermodynamics > Topic: Heat Capacity and Calorimetry and Measurement of Enthalpy