16 public questions tagged with this topic.
Number of lines = (n₂-n₁)(n₂-n₁+1)/2 = 6.
Ref: NCERT Class 11 Chemistry > Chapter 2: Structure of Atom > Topic: Shapes of Orbitals - s p d f and Nodes and Radial Probability
Wavenumber ν̄ = 4 × 1.097×10⁷ (1/1² - 1/2²) = 3.291×10⁷ m⁻¹. Frequency ν = c ν̄ = 3.0×10⁸ × 3.291×10⁷ = 9.873×10¹⁵ Hz.
Ref: NCERT Class 11 Chemistry > Chapter 2: Structure of Atom > Topic: Shapes of Orbitals - s p d f and Nodes and Radial Probability
Number of lines = (8-4)(8-4+1)/2 = 10; actual distinct transitions = 7.
Ref: NCERT Class 11 Chemistry > Chapter 2: Structure of Atom > Topic: Quantum Numbers - Principal Azimuthal Magnetic Spin
For Be³⁺ (Z=4), ΔE ≈ 2.903×10⁻¹⁸ J. λ ≈ 68.45 nm.
Ref: NCERT Class 11 Chemistry > Chapter 2: Structure of Atom > Topic: Quantum Numbers - Principal Azimuthal Magnetic Spin
ΔE ≈ 9.176×10⁻²⁰ J. ν ≈ 1.385×10¹⁴ Hz.
Ref: NCERT Class 11 Chemistry > Chapter 2: Structure of Atom > Topic: Quantum Mechanical Model - de Broglie Heisenberg and Schrodinger
Transitions: 4→2, 4→3→2, 3→2. Total = 3.
Ref: NCERT Class 11 Chemistry > Chapter 2: Structure of Atom > Topic: Electronic Configuration - Aufbau Pauli Hund and Stability
E₃ = -13.6 eV, E₆ = -3.4 eV. ΔE = 10.2 eV.
Ref: NCERT Class 11 Chemistry > Chapter 2: Structure of Atom > Topic: Electronic Configuration - Aufbau Pauli Hund and Stability
Number of lines = n(n-1)/2 = 10.
Ref: NCERT Class 11 Chemistry > Chapter 2: Structure of Atom > Topic: Developments Leading to Bohr Model - Electromagnetic Radiation and Spectrum
For B⁴⁺ (Z=5), ΔE = 71.4 eV. λ ≈ 17.41 nm.
Ref: NCERT Class 11 Chemistry > Chapter 2: Structure of Atom > Topic: Developments Leading to Bohr Model - Electromagnetic Radiation and Spectrum
ΔE = 10.2 eV. λ = hc/ΔE ≈ 121.7 nm.
Ref: NCERT Class 11 Chemistry > Chapter 2: Structure of Atom > Topic: Developments Leading to Bohr Model - Electromagnetic Radiation and Spectrum
Number of lines = (7-3)(7-3+1)/2 = 10.
Ref: NCERT Class 11 Chemistry > Chapter 2: Structure of Atom > Topic: Developments Leading to Bohr Model - Electromagnetic Radiation and Spectrum
ΔE = |E₁|(1 - 1/16) = 2.04375×10⁻¹⁸ J.
Ref: NCERT Class 11 Chemistry > Chapter 2: Structure of Atom > Topic: Developments Leading to Bohr Model - Electromagnetic Radiation and Spectrum
