6 public questions tagged with this topic.
E ≈ 5.301×10⁻¹⁹ J. KE ≈ 8.008×10⁻²⁰ J.
Ref: NCERT Class 11 Chemistry > Chapter 2: Structure of Atom > Topic: Shapes of Orbitals - s p d f and Nodes and Radial Probability
W₀ = hν₀. KE = h(ν - ν₀) ≈ 1.590×10⁻¹⁹ J.
Ref: NCERT Class 11 Chemistry > Chapter 2: Structure of Atom > Topic: Shapes of Orbitals - s p d f and Nodes and Radial Probability
E ≈ 3.55 eV. KE ≈ 0.35 eV ≈ 5.59×10⁻²⁰ J.
Ref: NCERT Class 11 Chemistry > Chapter 2: Structure of Atom > Topic: Quantum Numbers - Principal Azimuthal Magnetic Spin
E = hν ≈ 3.976×10⁻¹⁹ J. KE = E - W₀ ≈ 1.476×10⁻¹⁹ J.
Ref: NCERT Class 11 Chemistry > Chapter 2: Structure of Atom > Topic: Electronic Configuration - Aufbau Pauli Hund and Stability
W₀ ≈ 4.417×10⁻¹⁹ J. E = 6.626×10⁻¹⁹ J. KE ≈ 2.209×10⁻¹⁹ J.
Ref: NCERT Class 11 Chemistry > Chapter 2: Structure of Atom > Topic: Discovery of Subatomic Particles - Electron Proton Neutron
E ≈ 3.105 eV. KEmax = 1.105 eV ≈ 1.768×10⁻¹⁹ J.
Ref: NCERT Class 11 Chemistry > Chapter 2: Structure of Atom > Topic: Developments Leading to Bohr Model - Electromagnetic Radiation and Spectrum
