What is the total pressure at a depth of 3.6m in mercury (ρ\=13.6×103kg/m3) with atmospheric pressure 1.01×105Pa? (Take
Total pressure: P = Pa+ρgh. Pa = 1.01×105Pa, ρ = 13.6×103kg/m3, g = 9.8m/s2, h = 3.6m. P = 1.01×105+13.6×103×9.8×3.6 = 1.01×105+479808 = 5.80808×105Pa. As per NCERT, applying relevant law/formula with correct units and sign convention leads to 5.8 × 10⁵ Pa. This satisfies dimensional consistency and physical conditions given, so option B is scientifically correct.
Ref: NCBI Bookshelf, Ideal Gas Law: P1V1/T1 = P2V2/T2.