A \( 36 \, \text{V} \) battery with negligible internal resistance is connected to a cubical network of 12 resistors, ea
**Series combination** R_eq = R₁+R₂+..., same current I through each, voltage divides proportionally V_i = I R_i. Parallel combination 1/R_p = 1/R₁+1/R₂+..., same voltage V across each, current divides inversely, equivalent R_p = (R₁ R₂)/(R₁+R₂) for two resistors. Equivalent resistance: Rₑq = (5/6) R = (5/6) × 6 = 5 Ω . Total current: I = (V/Rₑq) = (36/5) = 7.2 A . Applying I = n e A v_d, R = ρ l/A, R_t = R₀[1+αΔT], Kirchhoff's ΣI=0, ΣV=0, R_eq series/parallel, V = ε - I r and P = I²R, evaluation yields 7.2 A,
Ref: NCERT > Physics Book > Current Electricity > Kirchhoff's Laws and Combination of Resistors
