#concentration change

Rate of Reaction - Average and Instantaneous Rate and Rate Law

A reaction has the rate law Rate = k[A]²[B]². If the concentration of A is doubled and B is reduced to half, what happen

New rate = k(2[A])²([B]/2)² = k×4×(1/4) = same as initial rate.

Ref: NCERT Class 12 Chemistry > Chapter 3: Chemical Kinetics > Topic: Rate of Reaction - Average and Instantaneous Rate and Rate Law

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Rate of Reaction - Average and Instantaneous Rate and Rate Law

A reaction has the rate law Rate = k[A]²[B]. If the concentration of A is tripled and B is doubled, by how many times wi

New rate = k(3[A])²(2[B]) = 9×2 = 18 times initial rate.

Ref: NCERT Class 12 Chemistry > Chapter 3: Chemical Kinetics > Topic: Rate of Reaction - Average and Instantaneous Rate and Rate Law

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Pseudo First Order and Complex Reactions

A zero-order reaction takes 120 s to reduce the concentration from 0.06 mol L⁻¹ to 0.03 mol L⁻¹. What is the rate consta

k = 0.03/120 = 2.5 × 10⁻⁴ mol L⁻¹ s⁻¹.

Ref: NCERT Class 12 Chemistry > Chapter 3: Chemical Kinetics > Topic: Pseudo First Order and Complex Reactions

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Pseudo First Order and Complex Reactions

For a reaction, the initial rate doubles when the concentration of the reactant is quadrupled. What is the order of the

4ⁿ = 2 → n = 0.5.

Ref: NCERT Class 12 Chemistry > Chapter 3: Chemical Kinetics > Topic: Pseudo First Order and Complex Reactions

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Pseudo First Order and Complex Reactions

A zero-order reaction takes 90 s to reduce the concentration from 0.15 mol L⁻¹ to 0.06 mol L⁻¹. What is the rate constan

k = (0.15 − 0.06)/90 = 1.0 × 10⁻³ mol L⁻¹ s⁻¹.

Ref: NCERT Class 12 Chemistry > Chapter 3: Chemical Kinetics > Topic: Pseudo First Order and Complex Reactions

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Pseudo First Order and Complex Reactions

A first-order reaction has an initial concentration of 0.8 mol L⁻¹. After 30 minutes, the concentration reduces to 0.4 m

k = (2.303/30) log(0.8/0.4) = (2.303×0.301)/30 ≈ 0.0231 min⁻¹.

Ref: NCERT Class 12 Chemistry > Chapter 3: Chemical Kinetics > Topic: Pseudo First Order and Complex Reactions

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Pseudo First Order and Complex Reactions

A reaction’s rate increases by 16 times when the concentration of the reactant is increased by 4 times. What is the orde

4ⁿ = 16 → n = 2.

Ref: NCERT Class 12 Chemistry > Chapter 3: Chemical Kinetics > Topic: Pseudo First Order and Complex Reactions

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Order and Molecularity and Units of Rate Constant

A reaction’s rate increases by 27 times when the concentration of the reactant is increased by 3 times. What is the orde

3ⁿ = 27 → n = 3.

Ref: NCERT Class 12 Chemistry > Chapter 3: Chemical Kinetics > Topic: Order and Molecularity and Units of Rate Constant

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Integrated Rate Equations - Zero Order Reactions

A reaction has the rate law Rate = k[A][B]^(1/2). If the concentration of A is doubled and B is quadrupled, what happens

New rate = 4 × initial rate.

Ref: NCERT Class 12 Chemistry > Chapter 3: Chemical Kinetics > Topic: Integrated Rate Equations - Zero Order Reactions

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Integrated Rate Equations - Zero Order Reactions

A reaction has the rate law Rate = k[A]²[B]. If the concentration of A is doubled and B is tripled, what happens to the

New rate = 12 × initial rate.

Ref: NCERT Class 12 Chemistry > Chapter 3: Chemical Kinetics > Topic: Integrated Rate Equations - Zero Order Reactions

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Integrated Rate Equations - Zero Order Reactions

A reaction has the rate law Rate = k[A]^(1/2)[B]. If the concentration of A is quadrupled and B is halved, what happens

New rate = same as initial rate.

Ref: NCERT Class 12 Chemistry > Chapter 3: Chemical Kinetics > Topic: Integrated Rate Equations - Zero Order Reactions

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Integrated Rate Equations - Zero Order Reactions

A reaction has the rate law Rate = k[A][B]². If the concentration of A is tripled and B is halved, what happens to the r

New rate = (3/4) × initial rate.

Ref: NCERT Class 12 Chemistry > Chapter 3: Chemical Kinetics > Topic: Integrated Rate Equations - Zero Order Reactions

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