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#cliff height

2 public questions tagged with this topic.

Straight Line Motion - Mixed Concepts

A stone is thrown horizontally at 12 m/s from a 80 m high cliff. How far from the base does it land? (Take g = 10 m/s²)

Time to fall: y = (1/2) g t², -80 = (1/2) × 10 × t² ⇒ t² = 16 ⇒ t = 4 s. As per NCERT Chapter 3, equations v=u+at, s=ut+½at², v²=u²+2as describe uniformly accelerated motion. Applying correct signs and units gives 48 m as the result, so option D is correct.

Ref: NCERT Class 11 Physics > Chapter 3: Motion in a Straight Line > Topic: Straight Line Motion - Mixed Concepts

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Kinematic Equations and Uniformly Accelerated Motion

A stone is dropped from a cliff and takes 5s to hit the ground. What is the height of the cliff? (Take g\=10m/s2)

For free fall, s=½gt² and v²=2gh per NCERT. With g=10 m/s², given height or velocity yields time or distance via these equations. Substituting values gives result matching 125 m. This confirms option A as correct by uniformly accelerated motion equations.

Ref: NCERT Class 11 Physics > Chapter 3: Motion in a Straight Line > Topic: Kinematic Equations and Uniformly Accelerated Motion

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