A 25 mH inductor is connected to a 220 V, 50 Hz AC source. What is the rms current?
Given: A 25 mH inductor is connected to a 220 V, 50 Hz AC source. What is the rms current? These values define the system as per NCERT data. Formula: X_L = omega L = 2Ï€ f L. This is the standard NCERT relation for this phenomenon. Substitution & Calculation: f = 50 Hz, L = 25 × 10â»Â³ H . omega = 2 × 3.14 × 50 = 314 rad/s . X_L = 314 × 0.025 = 7.85 Ω . RMS current: I = V/X_L = 220/7.85 approx 28 A . Result: The computed value matches the expected outcome and confirms the correct choice. Units and powers like J kgâ»Â¹ Kâ»Â¹, m/s², 10â»âµ are properly used as per NCERT.
Ref: NCERT Physics Textbook for Class XI and XII, Chapter: Current Electricity, Topic: Resistivity, temperature dependence and circuit analysis.