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Δ H = [2 × Δ Hf° (SO₃)] - [2 × Δ Hf° (SO₂) + Δ Hf° (O₂)] = [2 × (-395.7)] - [2 × (-296.8) + 0] = -791.4 + 593.6 = -197.8 kJ/mol.
Ref: NCERT Class 11 Chemistry > Chapter 5: Thermodynamics > Topic: Enthalpy Changes - Reaction Formation Combustion and Hess's Law
The standard enthalpy of formation is the enthalpy change when 1 mol of a compound is formed from its elements in their standard states, i.e., C(s) + O₂(g) → CO₂(g).
Ref: NCERT Class 11 Chemistry > Chapter 5: Thermodynamics > Topic: Enthalpy Changes - Reaction Formation Combustion and Hess's Law
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