7 public questions tagged with this topic.
In SO₂ , sulfur has three electron domains (two bonds, one lone pair), requiring sp² hybridization, leading to a bent shape.
Ref: NCERT Class 11 Chemistry > Chapter 4: Chemical Bonding and Molecular Structure > Topic: Valence Bond Theory and Hybridisation - sp sp2 sp3 dsp2
In XeF₂ , xenon has 8 valence electrons and forms 2 bonds (4 electrons used), leaving 4 electrons as 3 lone pairs. With sp³d hybridization, the 5 electron pairs (2 bonding, 3 lone) result in a trigonal bipyramidal electron geometry and a linear molecular shape.
Ref: NCERT Class 11 Chemistry > Chapter 4: Chemical Bonding and Molecular Structure > Topic: Valence Bond Theory and Hybridisation - sp sp2 sp3 dsp2
In CH₄ , carbon uses one s and three p orbitals to form four sp³ hybrid orbitals, resulting in a tetrahedral shape.
Ref: NCERT Class 11 Chemistry > Chapter 4: Chemical Bonding and Molecular Structure > Topic: Valence Bond Theory and Hybridisation - sp sp2 sp3 dsp2
In IF₇ , iodine has 7 bonding pairs and no lone pairs, requiring sp³d³ hybridization for a pentagonal bipyramidal shape.
Ref: NCERT Class 11 Chemistry > Chapter 4: Chemical Bonding and Molecular Structure > Topic: Kossel-Lewis Approach and Octet Rule and Lewis Structures
In PCl₅ , phosphorus has 5 bonds (10 electrons), exceeding the octet due to d-orbital availability.
Ref: NCERT Class 11 Chemistry > Chapter 4: Chemical Bonding and Molecular Structure > Topic: Kossel-Lewis Approach and Octet Rule and Lewis Structures
In AlCl₃ , aluminum forms three bonds, using 6 electrons, resulting in an incomplete octet.
Ref: NCERT Class 11 Chemistry > Chapter 4: Chemical Bonding and Molecular Structure > Topic: Kossel-Lewis Approach and Octet Rule and Lewis Structures
In OF₂ , oxygen is sp³ hybridized with two bonding pairs and two lone pairs, resulting in a bent (V-shaped) geometry.
Ref: NCERT Class 11 Chemistry > Chapter 4: Chemical Bonding and Molecular Structure > Topic: Ionic Bonding - Lattice Enthalpy and Properties of Ionic Compounds
